5y^2+2y-35=0

Solution for 5y^2+2y-35=0 equation:

5y^2+2y-35=0

a = 5; b = 2; c = -35;
Δ = b2-4ac
Δ = 22-4·5·(-35)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8\sqrt{11}}{2*5}=\frac{-2-8\sqrt{11}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8\sqrt{11}}{2*5}=\frac{-2+8\sqrt{11}}{10}
$